Leetcode[165] Compare Version Numbers

###Task1 Compare two version numbers version1 and version2. If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character. The . character does not represent a decimal point and is used to separate number sequences. For instance, 2.5 is not “two and a half” or “half way to version three”, it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

###Python ####simple

class Solution(object):
    def compareVersion(self, version1, version2):
        """
        :type version1: str
        :type version2: str
        :rtype: int
        """
        li1 = version1.split('.')
        li2 = version2.split('.')
        if len(li1) > len(li2):
            diff = len(li1) - len(li2)
            while diff:
                li2.append('0')
                diff -= 1
        else:
            diff = len(li2) - len(li1)
            while diff:
                li1.append('0')
                diff -= 1
        for i in range(len(li1)):
            if int(li1[i]) > int(li2[i]):
                return 1
            elif int(li1[i]) < int(li2[i]):
                return -1
        return 0

###Java

public class Solution {
    public int compareVersion(String version1, String version2) {
        if (version1 == null || version2 == null || version1.length() == 0 || version2.length() == 0) {
        	return 0;
        }

        String[] arr1 = version1.split("\\.");
        String[] arr2 = version2.split("\\.");

        int length1 = arr1.length;
        int length2 = arr2.length;

        if (length1 > length2) {
        	String[] extended1 = new String[length1];
        	String[] extended2 = new String[length1];

        	for (int i = 0; i < length1; i++) {
        		extended1[i] = arr1[i];
        		extended2[i] = i < length2 ? arr2[i] : "0";
        	}

	    	for (int i = 0; i < length1; i++) {
	    		if (Integer.parseInt(extended1[i]) > Integer.parseInt(extended2[i])) {
	    			return 1;
	    		}
	    		if (Integer.parseInt(extended1[i]) < Integer.parseInt(extended2[i])) {
	    			return -1;
	    		}
	    	}

        } else if (length1 <= length2) {
        	String[] extended1 = new String[length2];
        	String[] extended2 = new String[length2];

        	for (int i = 0; i < length2; i++) {
        		extended2[i] = arr2[i];
        		extended1[i] = i < length1 ? arr1[i] : "0";
        	}

	    	for (int i = 0; i < length2; i++) {
	    		if (Integer.parseInt(extended1[i]) > Integer.parseInt(extended2[i])) {
	    			return 1;
	    		}
	    		if (Integer.parseInt(extended1[i]) < Integer.parseInt(extended2[i])) {
	    			return -1;
	    		}
	    	}
        }


    	return 0;
    }

    public static void main(String[] args) {
    	Solution sol = new Solution();
    	System.out.println(sol.compareVersion("1", "1.1"));
    }
}

###Points